Metamath Proof Explorer
Description: Negation invariance for gcd. (Contributed by metakunt, 25-Apr-2024)
|
|
Ref |
Expression |
|
Hypotheses |
gcdnegnni.1 |
⊢ 𝑀 ∈ ℕ |
|
|
gcdnegnni.2 |
⊢ 𝑁 ∈ ℕ |
|
Assertion |
gcdnegnni |
⊢ ( 𝑀 gcd - 𝑁 ) = ( 𝑀 gcd 𝑁 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
gcdnegnni.1 |
⊢ 𝑀 ∈ ℕ |
2 |
|
gcdnegnni.2 |
⊢ 𝑁 ∈ ℕ |
3 |
1
|
nnzi |
⊢ 𝑀 ∈ ℤ |
4 |
2
|
nnzi |
⊢ 𝑁 ∈ ℤ |
5 |
3 4
|
pm3.2i |
⊢ ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) |
6 |
|
gcdneg |
⊢ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) → ( 𝑀 gcd - 𝑁 ) = ( 𝑀 gcd 𝑁 ) ) |
7 |
5 6
|
ax-mp |
⊢ ( 𝑀 gcd - 𝑁 ) = ( 𝑀 gcd 𝑁 ) |