Metamath Proof Explorer


Theorem ghmghmrn

Description: A group homomorphism from G to H is also a group homomorphism from G to its image in H . (Contributed by Paul Chapman, 3-Mar-2008) (Revised by AV, 26-Aug-2021)

Ref Expression
Hypothesis ghmghmrn.u 𝑈 = ( 𝑇s ran 𝐹 )
Assertion ghmghmrn ( 𝐹 ∈ ( 𝑆 GrpHom 𝑇 ) → 𝐹 ∈ ( 𝑆 GrpHom 𝑈 ) )

Proof

Step Hyp Ref Expression
1 ghmghmrn.u 𝑈 = ( 𝑇s ran 𝐹 )
2 ghmrn ( 𝐹 ∈ ( 𝑆 GrpHom 𝑇 ) → ran 𝐹 ∈ ( SubGrp ‘ 𝑇 ) )
3 ssid ran 𝐹 ⊆ ran 𝐹
4 1 resghm2b ( ( ran 𝐹 ∈ ( SubGrp ‘ 𝑇 ) ∧ ran 𝐹 ⊆ ran 𝐹 ) → ( 𝐹 ∈ ( 𝑆 GrpHom 𝑇 ) ↔ 𝐹 ∈ ( 𝑆 GrpHom 𝑈 ) ) )
5 3 4 mpan2 ( ran 𝐹 ∈ ( SubGrp ‘ 𝑇 ) → ( 𝐹 ∈ ( 𝑆 GrpHom 𝑇 ) ↔ 𝐹 ∈ ( 𝑆 GrpHom 𝑈 ) ) )
6 5 biimpd ( ran 𝐹 ∈ ( SubGrp ‘ 𝑇 ) → ( 𝐹 ∈ ( 𝑆 GrpHom 𝑇 ) → 𝐹 ∈ ( 𝑆 GrpHom 𝑈 ) ) )
7 2 6 mpcom ( 𝐹 ∈ ( 𝑆 GrpHom 𝑇 ) → 𝐹 ∈ ( 𝑆 GrpHom 𝑈 ) )