Metamath Proof Explorer


Theorem grpcominv2

Description: If two elements commute, then they commute with each other's inverses (case of the second element commuting with the inverse of the first element). (Contributed by SN, 1-Feb-2025)

Ref Expression
Hypotheses grpcominv.b ⊢ 𝐵 = ( Base ‘ 𝐺 )
grpcominv.p ⊢ + = ( +g ‘ 𝐺 )
grpcominv.n ⊢ 𝑁 = ( invg ‘ 𝐺 )
grpcominv.g ⊢ ( 𝜑 → 𝐺 ∈ Grp )
grpcominv.x ⊢ ( 𝜑 → 𝑋 ∈ 𝐵 )
grpcominv.y ⊢ ( 𝜑 → 𝑌 ∈ 𝐵 )
grpcominv.1 ⊢ ( 𝜑 → ( 𝑋 + 𝑌 ) = ( 𝑌 + 𝑋 ) )
Assertion grpcominv2 ( 𝜑 → ( 𝑌 + ( 𝑁 ‘ 𝑋 ) ) = ( ( 𝑁 ‘ 𝑋 ) + 𝑌 ) )

Proof

Step Hyp Ref Expression
1 grpcominv.b ⊢ 𝐵 = ( Base ‘ 𝐺 )
2 grpcominv.p ⊢ + = ( +g ‘ 𝐺 )
3 grpcominv.n ⊢ 𝑁 = ( invg ‘ 𝐺 )
4 grpcominv.g ⊢ ( 𝜑 → 𝐺 ∈ Grp )
5 grpcominv.x ⊢ ( 𝜑 → 𝑋 ∈ 𝐵 )
6 grpcominv.y ⊢ ( 𝜑 → 𝑌 ∈ 𝐵 )
7 grpcominv.1 ⊢ ( 𝜑 → ( 𝑋 + 𝑌 ) = ( 𝑌 + 𝑋 ) )
8 7 eqcomd ⊢ ( 𝜑 → ( 𝑌 + 𝑋 ) = ( 𝑋 + 𝑌 ) )
9 1 2 3 4 6 5 8 grpcominv1 ⊢ ( 𝜑 → ( 𝑌 + ( 𝑁 ‘ 𝑋 ) ) = ( ( 𝑁 ‘ 𝑋 ) + 𝑌 ) )