Metamath Proof Explorer


Theorem grpodivcl

Description: Closure of group division (or subtraction) operation. (Contributed by NM, 15-Feb-2008) (New usage is discouraged.)

Ref Expression
Hypotheses grpdivf.1 ⊢ 𝑋 = ran 𝐺
grpdivf.3 ⊢ 𝐷 = ( /𝑔 ‘ 𝐺 )
Assertion grpodivcl ( ( 𝐺 ∈ GrpOp ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ( 𝐴 𝐷 𝐵 ) ∈ 𝑋 )

Proof

Step Hyp Ref Expression
1 grpdivf.1 ⊢ 𝑋 = ran 𝐺
2 grpdivf.3 ⊢ 𝐷 = ( /𝑔 ‘ 𝐺 )
3 1 2 grpodivf ⊢ ( 𝐺 ∈ GrpOp → 𝐷 : ( 𝑋 × 𝑋 ) ⟶ 𝑋 )
4 fovcdm ⊢ ( ( 𝐷 : ( 𝑋 × 𝑋 ) ⟶ 𝑋 ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ( 𝐴 𝐷 𝐵 ) ∈ 𝑋 )
5 3 4 syl3an1 ⊢ ( ( 𝐺 ∈ GrpOp ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ( 𝐴 𝐷 𝐵 ) ∈ 𝑋 )