Metamath Proof Explorer


Theorem gruelss

Description: A Grothendieck universe is transitive, so each element is a subset of the universe. (Contributed by Mario Carneiro, 9-Jun-2013)

Ref Expression
Assertion gruelss ( ( 𝑈 ∈ Univ ∧ 𝐴 ∈ 𝑈 ) → 𝐴 ⊆ 𝑈 )

Proof

Step Hyp Ref Expression
1 grutr ⊢ ( 𝑈 ∈ Univ → Tr 𝑈 )
2 trss ⊢ ( Tr 𝑈 → ( 𝐴 ∈ 𝑈 → 𝐴 ⊆ 𝑈 ) )
3 2 imp ⊢ ( ( Tr 𝑈 ∧ 𝐴 ∈ 𝑈 ) → 𝐴 ⊆ 𝑈 )
4 1 3 sylan ⊢ ( ( 𝑈 ∈ Univ ∧ 𝐴 ∈ 𝑈 ) → 𝐴 ⊆ 𝑈 )