Metamath Proof Explorer


Theorem hashnnltb

Description: The # function on _om preserves the ordering. (Contributed by Eric Schmidt, 7-Jul-2026)

Ref Expression
Assertion hashnnltb ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ) → ( 𝐴𝐵 ↔ ( ♯ ‘ 𝐴 ) < ( ♯ ‘ 𝐵 ) ) )

Proof

Step Hyp Ref Expression
1 hashnnlt ( ( 𝐵 ∈ ω ∧ 𝐴𝐵 ) → ( ♯ ‘ 𝐴 ) < ( ♯ ‘ 𝐵 ) )
2 1 ex ( 𝐵 ∈ ω → ( 𝐴𝐵 → ( ♯ ‘ 𝐴 ) < ( ♯ ‘ 𝐵 ) ) )
3 2 adantl ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ) → ( 𝐴𝐵 → ( ♯ ‘ 𝐴 ) < ( ♯ ‘ 𝐵 ) ) )
4 hashss ( ( 𝐴 ∈ ω ∧ 𝐵𝐴 ) → ( ♯ ‘ 𝐵 ) ≤ ( ♯ ‘ 𝐴 ) )
5 4 ex ( 𝐴 ∈ ω → ( 𝐵𝐴 → ( ♯ ‘ 𝐵 ) ≤ ( ♯ ‘ 𝐴 ) ) )
6 5 adantr ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ) → ( 𝐵𝐴 → ( ♯ ‘ 𝐵 ) ≤ ( ♯ ‘ 𝐴 ) ) )
7 nnon ( 𝐵 ∈ ω → 𝐵 ∈ On )
8 nnon ( 𝐴 ∈ ω → 𝐴 ∈ On )
9 ontri1 ( ( 𝐵 ∈ On ∧ 𝐴 ∈ On ) → ( 𝐵𝐴 ↔ ¬ 𝐴𝐵 ) )
10 7 8 9 syl2anr ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ) → ( 𝐵𝐴 ↔ ¬ 𝐴𝐵 ) )
11 hashxrcl ( 𝐵 ∈ ω → ( ♯ ‘ 𝐵 ) ∈ ℝ* )
12 hashxrcl ( 𝐴 ∈ ω → ( ♯ ‘ 𝐴 ) ∈ ℝ* )
13 xrlenlt ( ( ( ♯ ‘ 𝐵 ) ∈ ℝ* ∧ ( ♯ ‘ 𝐴 ) ∈ ℝ* ) → ( ( ♯ ‘ 𝐵 ) ≤ ( ♯ ‘ 𝐴 ) ↔ ¬ ( ♯ ‘ 𝐴 ) < ( ♯ ‘ 𝐵 ) ) )
14 11 12 13 syl2anr ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ) → ( ( ♯ ‘ 𝐵 ) ≤ ( ♯ ‘ 𝐴 ) ↔ ¬ ( ♯ ‘ 𝐴 ) < ( ♯ ‘ 𝐵 ) ) )
15 6 10 14 3imtr3d ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ) → ( ¬ 𝐴𝐵 → ¬ ( ♯ ‘ 𝐴 ) < ( ♯ ‘ 𝐵 ) ) )
16 3 15 impcon4bid ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ) → ( 𝐴𝐵 ↔ ( ♯ ‘ 𝐴 ) < ( ♯ ‘ 𝐵 ) ) )