Metamath Proof Explorer


Theorem hbaltg

Description: A more general and closed form of hbal . (Contributed by Scott Fenton, 13-Dec-2010)

Ref Expression
Assertion hbaltg ( ∀ 𝑥 ( 𝜑 → ∀ 𝑦 𝜓 ) → ( ∀ 𝑥 𝜑 → ∀ 𝑦𝑥 𝜓 ) )

Proof

Step Hyp Ref Expression
1 alim ( ∀ 𝑥 ( 𝜑 → ∀ 𝑦 𝜓 ) → ( ∀ 𝑥 𝜑 → ∀ 𝑥𝑦 𝜓 ) )
2 ax-11 ( ∀ 𝑥𝑦 𝜓 → ∀ 𝑦𝑥 𝜓 )
3 1 2 syl6 ( ∀ 𝑥 ( 𝜑 → ∀ 𝑦 𝜓 ) → ( ∀ 𝑥 𝜑 → ∀ 𝑦𝑥 𝜓 ) )