Metamath Proof Explorer


Theorem hbalw

Description: Weak version of hbal . Uses only Tarski's FOL axiom schemes. Unlike hbal , this theorem requires that x and y be distinct, i.e., not be bundled. (Contributed by NM, 19-Apr-2017)

Ref Expression
Hypotheses hbalw.1 ( 𝑥 = 𝑧 → ( 𝜑𝜓 ) )
hbalw.2 ( 𝜑 → ∀ 𝑥 𝜑 )
Assertion hbalw ( ∀ 𝑦 𝜑 → ∀ 𝑥𝑦 𝜑 )

Proof

Step Hyp Ref Expression
1 hbalw.1 ( 𝑥 = 𝑧 → ( 𝜑𝜓 ) )
2 hbalw.2 ( 𝜑 → ∀ 𝑥 𝜑 )
3 2 alimi ( ∀ 𝑦 𝜑 → ∀ 𝑦𝑥 𝜑 )
4 1 alcomiw ( ∀ 𝑦𝑥 𝜑 → ∀ 𝑥𝑦 𝜑 )
5 3 4 syl ( ∀ 𝑦 𝜑 → ∀ 𝑥𝑦 𝜑 )