Metamath Proof Explorer


Theorem 19.8aw

Description: This is to 19.8a what spw is to sp . (Contributed by SN, 26-Sep-2024)

Ref Expression
Hypothesis 19.8aw.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
Assertion 19.8aw ( 𝜑 → ∃ 𝑥 𝜑 )

Proof

Step Hyp Ref Expression
1 19.8aw.1 ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
2 alnex ( ∀ 𝑥 ¬ 𝜑 ↔ ¬ ∃ 𝑥 𝜑 )
3 1 notbid ( 𝑥 = 𝑦 → ( ¬ 𝜑 ↔ ¬ 𝜓 ) )
4 3 spw ( ∀ 𝑥 ¬ 𝜑 → ¬ 𝜑 )
5 2 4 sylbir ( ¬ ∃ 𝑥 𝜑 → ¬ 𝜑 )
6 5 con4i ( 𝜑 → ∃ 𝑥 𝜑 )