Metamath Proof Explorer


Theorem ididg

Description: A set is identical to itself. (Contributed by NM, 28-May-2008) (Proof shortened by Andrew Salmon, 27-Aug-2011)

Ref Expression
Assertion ididg ( 𝐴 ∈ 𝑉 → 𝐴 I 𝐴 )

Proof

Step Hyp Ref Expression
1 eqid ⊢ 𝐴 = 𝐴
2 ideqg ⊢ ( 𝐴 ∈ 𝑉 → ( 𝐴 I 𝐴 ↔ 𝐴 = 𝐴 ) )
3 1 2 mpbiri ⊢ ( 𝐴 ∈ 𝑉 → 𝐴 I 𝐴 )