Metamath Proof Explorer


Theorem ididg

Description: A set is identical to itself. (Contributed by NM, 28-May-2008) (Proof shortened by Andrew Salmon, 27-Aug-2011)

Ref Expression
Assertion ididg AVAIA

Proof

Step Hyp Ref Expression
1 eqid A=A
2 ideqg AVAIAA=A
3 1 2 mpbiri AVAIA