Metamath Proof Explorer


Theorem ididg

Description: A set is identical to itself. (Contributed by NM, 28-May-2008) (Proof shortened by Andrew Salmon, 27-Aug-2011)

Ref Expression
Assertion ididg A V A I A

Proof

Step Hyp Ref Expression
1 eqid A = A
2 ideqg A V A I A A = A
3 1 2 mpbiri A V A I A