Metamath Proof Explorer


Theorem iineq1i

Description: Equality theorem for indexed intersection. Inference version. (Contributed by GG, 1-Sep-2025)

Ref Expression
Hypothesis iineq1i.1 ⊢ 𝐴 = 𝐵
Assertion iineq1i ∩ 𝑥 ∈ 𝐴 𝐶 = ∩ 𝑥 ∈ 𝐵 𝐶

Proof

Step Hyp Ref Expression
1 iineq1i.1 ⊢ 𝐴 = 𝐵
2 1 eleq2i ⊢ ( 𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐵 )
3 2 imbi1i ⊢ ( ( 𝑥 ∈ 𝐴 → 𝑡 ∈ 𝐶 ) ↔ ( 𝑥 ∈ 𝐵 → 𝑡 ∈ 𝐶 ) )
4 3 ralbii2 ⊢ ( ∀ 𝑥 ∈ 𝐴 𝑡 ∈ 𝐶 ↔ ∀ 𝑥 ∈ 𝐵 𝑡 ∈ 𝐶 )
5 4 abbii ⊢ { 𝑡 ∣ ∀ 𝑥 ∈ 𝐴 𝑡 ∈ 𝐶 } = { 𝑡 ∣ ∀ 𝑥 ∈ 𝐵 𝑡 ∈ 𝐶 }
6 df-iin ⊢ ∩ 𝑥 ∈ 𝐴 𝐶 = { 𝑡 ∣ ∀ 𝑥 ∈ 𝐴 𝑡 ∈ 𝐶 }
7 df-iin ⊢ ∩ 𝑥 ∈ 𝐵 𝐶 = { 𝑡 ∣ ∀ 𝑥 ∈ 𝐵 𝑡 ∈ 𝐶 }
8 5 6 7 3eqtr4i ⊢ ∩ 𝑥 ∈ 𝐴 𝐶 = ∩ 𝑥 ∈ 𝐵 𝐶