Metamath Proof Explorer


Theorem imbi1i

Description: Introduce a consequent to both sides of a logical equivalence. (Contributed by NM, 3-Jan-1993) (Proof shortened by Wolf Lammen, 17-Sep-2013)

Ref Expression
Hypothesis imbi1i.1 ( 𝜑𝜓 )
Assertion imbi1i ( ( 𝜑𝜒 ) ↔ ( 𝜓𝜒 ) )

Proof

Step Hyp Ref Expression
1 imbi1i.1 ( 𝜑𝜓 )
2 imbi1 ( ( 𝜑𝜓 ) → ( ( 𝜑𝜒 ) ↔ ( 𝜓𝜒 ) ) )
3 1 2 ax-mp ( ( 𝜑𝜒 ) ↔ ( 𝜓𝜒 ) )