Metamath Proof Explorer


Theorem in13

Description: A rearrangement of intersection. (Contributed by NM, 27-Aug-2012)

Ref Expression
Assertion in13 ( 𝐴 ∩ ( 𝐵 ∩ 𝐶 ) ) = ( 𝐶 ∩ ( 𝐵 ∩ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 in32 ⊢ ( ( 𝐵 ∩ 𝐶 ) ∩ 𝐴 ) = ( ( 𝐵 ∩ 𝐴 ) ∩ 𝐶 )
2 incom ⊢ ( 𝐴 ∩ ( 𝐵 ∩ 𝐶 ) ) = ( ( 𝐵 ∩ 𝐶 ) ∩ 𝐴 )
3 incom ⊢ ( 𝐶 ∩ ( 𝐵 ∩ 𝐴 ) ) = ( ( 𝐵 ∩ 𝐴 ) ∩ 𝐶 )
4 1 2 3 3eqtr4i ⊢ ( 𝐴 ∩ ( 𝐵 ∩ 𝐶 ) ) = ( 𝐶 ∩ ( 𝐵 ∩ 𝐴 ) )