Metamath Proof Explorer


Theorem inegd

Description: Negation introduction rule from natural deduction. (Contributed by Mario Carneiro, 9-Feb-2017)

Ref Expression
Hypothesis inegd.1 ( ( 𝜑𝜓 ) → ⊥ )
Assertion inegd ( 𝜑 → ¬ 𝜓 )

Proof

Step Hyp Ref Expression
1 inegd.1 ( ( 𝜑𝜓 ) → ⊥ )
2 1 ex ( 𝜑 → ( 𝜓 → ⊥ ) )
3 dfnot ( ¬ 𝜓 ↔ ( 𝜓 → ⊥ ) )
4 2 3 sylibr ( 𝜑 → ¬ 𝜓 )