Metamath Proof Explorer


Theorem ineqan12d

Description: Equality deduction for intersection of two classes. (Contributed by NM, 7-Feb-2007)

Ref Expression
Hypotheses ineq1d.1 ( 𝜑𝐴 = 𝐵 )
ineqan12d.2 ( 𝜓𝐶 = 𝐷 )
Assertion ineqan12d ( ( 𝜑𝜓 ) → ( 𝐴𝐶 ) = ( 𝐵𝐷 ) )

Proof

Step Hyp Ref Expression
1 ineq1d.1 ( 𝜑𝐴 = 𝐵 )
2 ineqan12d.2 ( 𝜓𝐶 = 𝐷 )
3 ineq12 ( ( 𝐴 = 𝐵𝐶 = 𝐷 ) → ( 𝐴𝐶 ) = ( 𝐵𝐷 ) )
4 1 2 3 syl2an ( ( 𝜑𝜓 ) → ( 𝐴𝐶 ) = ( 𝐵𝐷 ) )