Metamath Proof Explorer


Theorem ineqan12d

Description: Equality deduction for intersection of two classes. (Contributed by NM, 7-Feb-2007)

Ref Expression
Hypotheses ineq1d.1 ⊢ φ → A = B
ineqan12d.2 ⊢ ψ → C = D
Assertion ineqan12d ⊢ φ ∧ ψ → A ∩ C = B ∩ D

Proof

Step Hyp Ref Expression
1 ineq1d.1 ⊢ φ → A = B
2 ineqan12d.2 ⊢ ψ → C = D
3 ineq12 ⊢ A = B ∧ C = D → A ∩ C = B ∩ D
4 1 2 3 syl2an ⊢ φ ∧ ψ → A ∩ C = B ∩ D