Metamath Proof Explorer


Theorem iotabii

Description: Formula-building deduction for iota. (Contributed by Mario Carneiro, 2-Oct-2015)

Ref Expression
Hypothesis iotabii.1 ⊢ ( 𝜑 ↔ 𝜓 )
Assertion iotabii ( ℩ 𝑥 𝜑 ) = ( ℩ 𝑥 𝜓 )

Proof

Step Hyp Ref Expression
1 iotabii.1 ⊢ ( 𝜑 ↔ 𝜓 )
2 iotabi ⊢ ( ∀ 𝑥 ( 𝜑 ↔ 𝜓 ) → ( ℩ 𝑥 𝜑 ) = ( ℩ 𝑥 𝜓 ) )
3 2 1 mpg ⊢ ( ℩ 𝑥 𝜑 ) = ( ℩ 𝑥 𝜓 )