Metamath Proof Explorer


Theorem isdrng3lem0

Description: Lemma for isdrng3 : The base set of a multipication group restricted to a subset of the original base set. (Contributed by AV, 22-Jul-2026)

Ref Expression
Hypothesis isdrng3.b 𝐵 = ( Base ‘ 𝑅 )
Assertion isdrng3lem0 ( Base ‘ ( ( mulGrp ‘ 𝑅 ) ↾s ( 𝐵𝑋 ) ) ) = ( 𝐵𝑋 )

Proof

Step Hyp Ref Expression
1 isdrng3.b 𝐵 = ( Base ‘ 𝑅 )
2 difss ( 𝐵𝑋 ) ⊆ 𝐵
3 eqid ( ( mulGrp ‘ 𝑅 ) ↾s ( 𝐵𝑋 ) ) = ( ( mulGrp ‘ 𝑅 ) ↾s ( 𝐵𝑋 ) )
4 eqid ( mulGrp ‘ 𝑅 ) = ( mulGrp ‘ 𝑅 )
5 4 1 mgpbas 𝐵 = ( Base ‘ ( mulGrp ‘ 𝑅 ) )
6 3 5 ressbas2 ( ( 𝐵𝑋 ) ⊆ 𝐵 → ( 𝐵𝑋 ) = ( Base ‘ ( ( mulGrp ‘ 𝑅 ) ↾s ( 𝐵𝑋 ) ) ) )
7 6 eqcomd ( ( 𝐵𝑋 ) ⊆ 𝐵 → ( Base ‘ ( ( mulGrp ‘ 𝑅 ) ↾s ( 𝐵𝑋 ) ) ) = ( 𝐵𝑋 ) )
8 2 7 ax-mp ( Base ‘ ( ( mulGrp ‘ 𝑅 ) ↾s ( 𝐵𝑋 ) ) ) = ( 𝐵𝑋 )