Metamath Proof Explorer


Theorem isdrng3lem0

Description: Lemma for isdrng3 : The base set of a multipication group restricted to a subset of the original base set. (Contributed by AV, 22-Jul-2026)

Ref Expression
Hypothesis isdrng3.b
|- B = ( Base ` R )
Assertion isdrng3lem0
|- ( Base ` ( ( mulGrp ` R ) |`s ( B \ X ) ) ) = ( B \ X )

Proof

Step Hyp Ref Expression
1 isdrng3.b
 |-  B = ( Base ` R )
2 difss
 |-  ( B \ X ) C_ B
3 eqid
 |-  ( ( mulGrp ` R ) |`s ( B \ X ) ) = ( ( mulGrp ` R ) |`s ( B \ X ) )
4 eqid
 |-  ( mulGrp ` R ) = ( mulGrp ` R )
5 4 1 mgpbas
 |-  B = ( Base ` ( mulGrp ` R ) )
6 3 5 ressbas2
 |-  ( ( B \ X ) C_ B -> ( B \ X ) = ( Base ` ( ( mulGrp ` R ) |`s ( B \ X ) ) ) )
7 6 eqcomd
 |-  ( ( B \ X ) C_ B -> ( Base ` ( ( mulGrp ` R ) |`s ( B \ X ) ) ) = ( B \ X ) )
8 2 7 ax-mp
 |-  ( Base ` ( ( mulGrp ` R ) |`s ( B \ X ) ) ) = ( B \ X )