Metamath Proof Explorer


Theorem isidom2

Description: The predicate "is an integral domain": An integral domain is a commutative prime ring. (Contributed by Jeff Madsen, 10-Jun-2010) (Revised by AV, 27-Jun-2026)

Ref Expression
Assertion isidom2 ( 𝑅 ∈ IDomn ↔ ( 𝑅 ∈ PrmRing ∧ 𝑅 ∈ CRing ) )

Proof

Step Hyp Ref Expression
1 dfidom2 IDomn = ( PrmRing ∩ CRing )
2 1 elin2 ( 𝑅 ∈ IDomn ↔ ( 𝑅 ∈ PrmRing ∧ 𝑅 ∈ CRing ) )