Metamath Proof Explorer


Theorem jao

Description: Disjunction of antecedents. Compare Theorem *3.44 of WhiteheadRussell p. 113. (Contributed by NM, 5-Apr-1994) (Proof shortened by Wolf Lammen, 4-Apr-2013)

Ref Expression
Assertion jao ( ( 𝜑 → 𝜓 ) → ( ( 𝜒 → 𝜓 ) → ( ( 𝜑 ∨ 𝜒 ) → 𝜓 ) ) )

Proof

Step Hyp Ref Expression
1 pm3.44 ⊢ ( ( ( 𝜑 → 𝜓 ) ∧ ( 𝜒 → 𝜓 ) ) → ( ( 𝜑 ∨ 𝜒 ) → 𝜓 ) )
2 1 ex ⊢ ( ( 𝜑 → 𝜓 ) → ( ( 𝜒 → 𝜓 ) → ( ( 𝜑 ∨ 𝜒 ) → 𝜓 ) ) )