Database
SUPPLEMENTARY MATERIAL (USERS' MATHBOXES)
Mathbox for BTernaryTau
ZF set theory
Cardinality without the Axiom of Choice
kardcard
Metamath Proof Explorer
Description: Two sets have equal kard cardinalities iff they have equal card
cardinalities. This theorem depends on the Axiom of Choice. (Contributed by BTernaryTau , 3-Jul-2026)
Ref
Expression
Assertion
kardcard
⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → ( ( kard ‘ 𝐴 ) = ( kard ‘ 𝐵 ) ↔ ( card ‘ 𝐴 ) = ( card ‘ 𝐵 ) ) )
Proof
Step
Hyp
Ref
Expression
1
axac3
⊢ CHOICE
2
ackardcard
⊢ ( CHOICE → ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → ( ( kard ‘ 𝐴 ) = ( kard ‘ 𝐵 ) ↔ ( card ‘ 𝐴 ) = ( card ‘ 𝐵 ) ) ) )
3
1 2
ax-mp
⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → ( ( kard ‘ 𝐴 ) = ( kard ‘ 𝐵 ) ↔ ( card ‘ 𝐴 ) = ( card ‘ 𝐵 ) ) )