Metamath Proof Explorer


Theorem ackardcard

Description: The Axiom of Choice implies that two sets have equal kard cardinalities iff they have equal card cardinalities. (Contributed by BTernaryTau, 3-Jul-2026)

Ref Expression
Assertion ackardcard ( CHOICE → ( ( 𝐴𝑉𝐵𝑊 ) → ( ( kard ‘ 𝐴 ) = ( kard ‘ 𝐵 ) ↔ ( card ‘ 𝐴 ) = ( card ‘ 𝐵 ) ) ) )

Proof

Step Hyp Ref Expression
1 acnum ( CHOICE → ( 𝐴𝑉𝐴 ∈ dom card ) )
2 acnum ( CHOICE → ( 𝐵𝑊𝐵 ∈ dom card ) )
3 1 2 anim12d ( CHOICE → ( ( 𝐴𝑉𝐵𝑊 ) → ( 𝐴 ∈ dom card ∧ 𝐵 ∈ dom card ) ) )
4 kardcard2 ( ( 𝐴 ∈ dom card ∧ 𝐵 ∈ dom card ) → ( ( kard ‘ 𝐴 ) = ( kard ‘ 𝐵 ) ↔ ( card ‘ 𝐴 ) = ( card ‘ 𝐵 ) ) )
5 3 4 syl6 ( CHOICE → ( ( 𝐴𝑉𝐵𝑊 ) → ( ( kard ‘ 𝐴 ) = ( kard ‘ 𝐵 ) ↔ ( card ‘ 𝐴 ) = ( card ‘ 𝐵 ) ) ) )