Metamath Proof Explorer


Theorem ackardcard

Description: The Axiom of Choice implies that two sets have equal kard cardinalities iff they have equal card cardinalities. (Contributed by BTernaryTau, 3-Jul-2026)

Ref Expression
Assertion ackardcard
|- ( CHOICE -> ( ( A e. V /\ B e. W ) -> ( ( kard ` A ) = ( kard ` B ) <-> ( card ` A ) = ( card ` B ) ) ) )

Proof

Step Hyp Ref Expression
1 acnum
 |-  ( CHOICE -> ( A e. V -> A e. dom card ) )
2 acnum
 |-  ( CHOICE -> ( B e. W -> B e. dom card ) )
3 1 2 anim12d
 |-  ( CHOICE -> ( ( A e. V /\ B e. W ) -> ( A e. dom card /\ B e. dom card ) ) )
4 kardcard2
 |-  ( ( A e. dom card /\ B e. dom card ) -> ( ( kard ` A ) = ( kard ` B ) <-> ( card ` A ) = ( card ` B ) ) )
5 3 4 syl6
 |-  ( CHOICE -> ( ( A e. V /\ B e. W ) -> ( ( kard ` A ) = ( kard ` B ) <-> ( card ` A ) = ( card ` B ) ) ) )