Metamath Proof Explorer


Theorem kardenir

Description: If two sets are equinumerous, then their kard cardinal numbers are equal. (Contributed by BTernaryTau, 4-Jul-2026)

Ref Expression
Assertion kardenir ( 𝐴 ≈ 𝐵 → ( kard ‘ 𝐴 ) = ( kard ‘ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 relen ⊢ Rel ≈
2 1 brrelex1i ⊢ ( 𝐴 ≈ 𝐵 → 𝐴 ∈ V )
3 kardeng ⊢ ( 𝐴 ∈ V → ( ( kard ‘ 𝐴 ) = ( kard ‘ 𝐵 ) ↔ 𝐴 ≈ 𝐵 ) )
4 2 3 syl ⊢ ( 𝐴 ≈ 𝐵 → ( ( kard ‘ 𝐴 ) = ( kard ‘ 𝐵 ) ↔ 𝐴 ≈ 𝐵 ) )
5 4 ibir ⊢ ( 𝐴 ≈ 𝐵 → ( kard ‘ 𝐴 ) = ( kard ‘ 𝐵 ) )