Metamath Proof Explorer


Theorem kardenir

Description: If two sets are equinumerous, then their kard cardinal numbers are equal. (Contributed by BTernaryTau, 4-Jul-2026)

Ref Expression
Assertion kardenir ( 𝐴𝐵 → ( kard ‘ 𝐴 ) = ( kard ‘ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 relen Rel ≈
2 1 brrelex1i ( 𝐴𝐵𝐴 ∈ V )
3 kardeng ( 𝐴 ∈ V → ( ( kard ‘ 𝐴 ) = ( kard ‘ 𝐵 ) ↔ 𝐴𝐵 ) )
4 2 3 syl ( 𝐴𝐵 → ( ( kard ‘ 𝐴 ) = ( kard ‘ 𝐵 ) ↔ 𝐴𝐵 ) )
5 4 ibir ( 𝐴𝐵 → ( kard ‘ 𝐴 ) = ( kard ‘ 𝐵 ) )