Metamath Proof Explorer


Theorem kard0b

Description: The empty set is the only set with cardinality zero. This is the kard version of cardeq0 . (Contributed by BTernaryTau, 3-Jul-2026)

Ref Expression
Assertion kard0b ( ( kard ‘ 𝐴 ) = ( kard ‘ ∅ ) ↔ 𝐴 = ∅ )

Proof

Step Hyp Ref Expression
1 kardeng ( 𝐴 ∈ V → ( ( kard ‘ 𝐴 ) = ( kard ‘ ∅ ) ↔ 𝐴 ≈ ∅ ) )
2 en0 ( 𝐴 ≈ ∅ ↔ 𝐴 = ∅ )
3 1 2 bitrdi ( 𝐴 ∈ V → ( ( kard ‘ 𝐴 ) = ( kard ‘ ∅ ) ↔ 𝐴 = ∅ ) )
4 fvprc ( ¬ 𝐴 ∈ V → ( kard ‘ 𝐴 ) = ∅ )
5 0nep0 ∅ ≠ { ∅ }
6 kard0 ( kard ‘ ∅ ) = { ∅ }
7 5 6 neeqtrri ∅ ≠ ( kard ‘ ∅ )
8 7 a1i ( ¬ 𝐴 ∈ V → ∅ ≠ ( kard ‘ ∅ ) )
9 4 8 eqnetrd ( ¬ 𝐴 ∈ V → ( kard ‘ 𝐴 ) ≠ ( kard ‘ ∅ ) )
10 9 neneqd ( ¬ 𝐴 ∈ V → ¬ ( kard ‘ 𝐴 ) = ( kard ‘ ∅ ) )
11 0ex ∅ ∈ V
12 eleq1 ( 𝐴 = ∅ → ( 𝐴 ∈ V ↔ ∅ ∈ V ) )
13 11 12 mpbiri ( 𝐴 = ∅ → 𝐴 ∈ V )
14 13 con3i ( ¬ 𝐴 ∈ V → ¬ 𝐴 = ∅ )
15 10 14 2falsed ( ¬ 𝐴 ∈ V → ( ( kard ‘ 𝐴 ) = ( kard ‘ ∅ ) ↔ 𝐴 = ∅ ) )
16 3 15 pm2.61i ( ( kard ‘ 𝐴 ) = ( kard ‘ ∅ ) ↔ 𝐴 = ∅ )