Metamath Proof Explorer


Theorem kardsn

Description: A singleton has cardinality one. (Contributed by BTernaryTau, 4-Jul-2026)

Ref Expression
Assertion kardsn ( 𝐴𝑉 → ( kard ‘ { 𝐴 } ) = ( kard ‘ 1o ) )

Proof

Step Hyp Ref Expression
1 ensn1g ( 𝐴𝑉 → { 𝐴 } ≈ 1o )
2 snex { 𝐴 } ∈ V
3 kardeng ( { 𝐴 } ∈ V → ( ( kard ‘ { 𝐴 } ) = ( kard ‘ 1o ) ↔ { 𝐴 } ≈ 1o ) )
4 2 3 ax-mp ( ( kard ‘ { 𝐴 } ) = ( kard ‘ 1o ) ↔ { 𝐴 } ≈ 1o )
5 1 4 sylibr ( 𝐴𝑉 → ( kard ‘ { 𝐴 } ) = ( kard ‘ 1o ) )