Metamath Proof Explorer
Description: Two falsehoods are equivalent (deduction form). (Contributed by NM, 11-Oct-2013) (Proof shortened by Wolf Lammen, 11-Apr-2024)
|
|
Ref |
Expression |
|
Hypotheses |
2falsed.1 |
⊢ ( 𝜑 → ¬ 𝜓 ) |
|
|
2falsed.2 |
⊢ ( 𝜑 → ¬ 𝜒 ) |
|
Assertion |
2falsed |
⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
2falsed.1 |
⊢ ( 𝜑 → ¬ 𝜓 ) |
2 |
|
2falsed.2 |
⊢ ( 𝜑 → ¬ 𝜒 ) |
3 |
1 2
|
2thd |
⊢ ( 𝜑 → ( ¬ 𝜓 ↔ ¬ 𝜒 ) ) |
4 |
3
|
con4bid |
⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) ) |