Metamath Proof Explorer


Theorem kard0

Description: The kard cardinality of the empty set is the singleton of the empty set. (Contributed by BTernaryTau, 3-Jul-2026)

Ref Expression
Assertion kard0 ( kard ‘ ∅ ) = { ∅ }

Proof

Step Hyp Ref Expression
1 0ex ⊢ ∅ ∈ V
2 breq2 ⊢ ( 𝑥 = ∅ → ( 𝑦 ≈ 𝑥 ↔ 𝑦 ≈ ∅ ) )
3 2 abbidv ⊢ ( 𝑥 = ∅ → { 𝑦 ∣ 𝑦 ≈ 𝑥 } = { 𝑦 ∣ 𝑦 ≈ ∅ } )
4 3 scotteqd ⊢ ( 𝑥 = ∅ → Scott { 𝑦 ∣ 𝑦 ≈ 𝑥 } = Scott { 𝑦 ∣ 𝑦 ≈ ∅ } )
5 en0 ⊢ ( 𝑦 ≈ ∅ ↔ 𝑦 = ∅ )
6 velsn ⊢ ( 𝑦 ∈ { ∅ } ↔ 𝑦 = ∅ )
7 5 6 bitr4i ⊢ ( 𝑦 ≈ ∅ ↔ 𝑦 ∈ { ∅ } )
8 7 a1i ⊢ ( ⊤ → ( 𝑦 ≈ ∅ ↔ 𝑦 ∈ { ∅ } ) )
9 8 eqabcdv ⊢ ( ⊤ → { 𝑦 ∣ 𝑦 ≈ ∅ } = { ∅ } )
10 9 mptru ⊢ { 𝑦 ∣ 𝑦 ≈ ∅ } = { ∅ }
11 10 scotteqi ⊢ Scott { 𝑦 ∣ 𝑦 ≈ ∅ } = Scott { ∅ }
12 scottsn ⊢ Scott { ∅ } = { ∅ }
13 11 12 eqtri ⊢ Scott { 𝑦 ∣ 𝑦 ≈ ∅ } = { ∅ }
14 4 13 eqtrdi ⊢ ( 𝑥 = ∅ → Scott { 𝑦 ∣ 𝑦 ≈ 𝑥 } = { ∅ } )
15 df-kard ⊢ kard = ( 𝑥 ∈ V ↦ Scott { 𝑦 ∣ 𝑦 ≈ 𝑥 } )
16 snex ⊢ { ∅ } ∈ V
17 14 15 16 fvmpt ⊢ ( ∅ ∈ V → ( kard ‘ ∅ ) = { ∅ } )
18 1 17 ax-mp ⊢ ( kard ‘ ∅ ) = { ∅ }