Metamath Proof Explorer


Theorem scotteqi

Description: Equality theorem for the Scott operation. Inference form of scotteq . (Contributed by BTernaryTau, 3-Jul-2026)

Ref Expression
Hypothesis scotteqi.1 𝐴 = 𝐵
Assertion scotteqi Scott 𝐴 = Scott 𝐵

Proof

Step Hyp Ref Expression
1 scotteqi.1 𝐴 = 𝐵
2 scotteq ( 𝐴 = 𝐵 → Scott 𝐴 = Scott 𝐵 )
3 1 2 ax-mp Scott 𝐴 = Scott 𝐵