Metamath Proof Explorer


Theorem scotteqi

Description: Equality theorem for the Scott operation. Inference form of scotteq . (Contributed by BTernaryTau, 3-Jul-2026)

Ref Expression
Hypothesis scotteqi.1
|- A = B
Assertion scotteqi
|- Scott A = Scott B

Proof

Step Hyp Ref Expression
1 scotteqi.1
 |-  A = B
2 scotteq
 |-  ( A = B -> Scott A = Scott B )
3 1 2 ax-mp
 |-  Scott A = Scott B