Metamath Proof Explorer


Theorem lesnltd

Description: Surreal less-than or equal in terms of less-than. Deduction version. (Contributed by Scott Fenton, 25-Feb-2026)

Ref Expression
Hypotheses lesd.1 ⊢ ( 𝜑 → 𝐴 ∈ No )
lesd.2 ⊢ ( 𝜑 → 𝐵 ∈ No )
Assertion lesnltd ( 𝜑 → ( 𝐴 ≤s 𝐵 ↔ ¬ 𝐵 <s 𝐴 ) )

Proof

Step Hyp Ref Expression
1 lesd.1 ⊢ ( 𝜑 → 𝐴 ∈ No )
2 lesd.2 ⊢ ( 𝜑 → 𝐵 ∈ No )
3 lenlts ⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) → ( 𝐴 ≤s 𝐵 ↔ ¬ 𝐵 <s 𝐴 ) )
4 1 2 3 syl2anc ⊢ ( 𝜑 → ( 𝐴 ≤s 𝐵 ↔ ¬ 𝐵 <s 𝐴 ) )