Metamath Proof Explorer


Theorem ltsn0

Description: If X is less than Y , then either (LeftY ) or ( RightX ) is non-empty. (Contributed by Scott Fenton, 10-Dec-2024)

Ref Expression
Assertion ltsn0 ( ( 𝑋 ∈ No ∧ 𝑌 ∈ No ∧ 𝑋 <s 𝑌 ) → ( ( L ‘ 𝑌 ) ≠ ∅ ∨ ( R ‘ 𝑋 ) ≠ ∅ ) )

Proof

Step Hyp Ref Expression
1 lltr ⊢ ( L ‘ 𝑋 ) <<s ( R ‘ 𝑋 )
2 1 a1i ⊢ ( ( 𝑋 ∈ No ∧ 𝑌 ∈ No ) → ( L ‘ 𝑋 ) <<s ( R ‘ 𝑋 ) )
3 lltr ⊢ ( L ‘ 𝑌 ) <<s ( R ‘ 𝑌 )
4 3 a1i ⊢ ( ( 𝑋 ∈ No ∧ 𝑌 ∈ No ) → ( L ‘ 𝑌 ) <<s ( R ‘ 𝑌 ) )
5 lrcut ⊢ ( 𝑋 ∈ No → ( ( L ‘ 𝑋 ) |s ( R ‘ 𝑋 ) ) = 𝑋 )
6 5 eqcomd ⊢ ( 𝑋 ∈ No → 𝑋 = ( ( L ‘ 𝑋 ) |s ( R ‘ 𝑋 ) ) )
7 6 adantr ⊢ ( ( 𝑋 ∈ No ∧ 𝑌 ∈ No ) → 𝑋 = ( ( L ‘ 𝑋 ) |s ( R ‘ 𝑋 ) ) )
8 lrcut ⊢ ( 𝑌 ∈ No → ( ( L ‘ 𝑌 ) |s ( R ‘ 𝑌 ) ) = 𝑌 )
9 8 eqcomd ⊢ ( 𝑌 ∈ No → 𝑌 = ( ( L ‘ 𝑌 ) |s ( R ‘ 𝑌 ) ) )
10 9 adantl ⊢ ( ( 𝑋 ∈ No ∧ 𝑌 ∈ No ) → 𝑌 = ( ( L ‘ 𝑌 ) |s ( R ‘ 𝑌 ) ) )
11 2 4 7 10 ltsrecd ⊢ ( ( 𝑋 ∈ No ∧ 𝑌 ∈ No ) → ( 𝑋 <s 𝑌 ↔ ( ∃ 𝑦 ∈ ( L ‘ 𝑌 ) 𝑋 ≤s 𝑦 ∨ ∃ 𝑥 ∈ ( R ‘ 𝑋 ) 𝑥 ≤s 𝑌 ) ) )
12 11 biimp3a ⊢ ( ( 𝑋 ∈ No ∧ 𝑌 ∈ No ∧ 𝑋 <s 𝑌 ) → ( ∃ 𝑦 ∈ ( L ‘ 𝑌 ) 𝑋 ≤s 𝑦 ∨ ∃ 𝑥 ∈ ( R ‘ 𝑋 ) 𝑥 ≤s 𝑌 ) )
13 rexn0 ⊢ ( ∃ 𝑦 ∈ ( L ‘ 𝑌 ) 𝑋 ≤s 𝑦 → ( L ‘ 𝑌 ) ≠ ∅ )
14 rexn0 ⊢ ( ∃ 𝑥 ∈ ( R ‘ 𝑋 ) 𝑥 ≤s 𝑌 → ( R ‘ 𝑋 ) ≠ ∅ )
15 13 14 orim12i ⊢ ( ( ∃ 𝑦 ∈ ( L ‘ 𝑌 ) 𝑋 ≤s 𝑦 ∨ ∃ 𝑥 ∈ ( R ‘ 𝑋 ) 𝑥 ≤s 𝑌 ) → ( ( L ‘ 𝑌 ) ≠ ∅ ∨ ( R ‘ 𝑋 ) ≠ ∅ ) )
16 12 15 syl ⊢ ( ( 𝑋 ∈ No ∧ 𝑌 ∈ No ∧ 𝑋 <s 𝑌 ) → ( ( L ‘ 𝑌 ) ≠ ∅ ∨ ( R ‘ 𝑋 ) ≠ ∅ ) )