Metamath Proof Explorer


Theorem ltsub2dd

Description: Subtraction of both sides of 'less than'. (Contributed by Mario Carneiro, 30-May-2016)

Ref Expression
Hypotheses leidd.1 ⊢ ( 𝜑 → 𝐴 ∈ ℝ )
ltnegd.2 ⊢ ( 𝜑 → 𝐵 ∈ ℝ )
ltadd1d.3 ⊢ ( 𝜑 → 𝐶 ∈ ℝ )
ltadd1dd.4 ⊢ ( 𝜑 → 𝐴 < 𝐵 )
Assertion ltsub2dd ( 𝜑 → ( 𝐶 − 𝐵 ) < ( 𝐶 − 𝐴 ) )

Proof

Step Hyp Ref Expression
1 leidd.1 ⊢ ( 𝜑 → 𝐴 ∈ ℝ )
2 ltnegd.2 ⊢ ( 𝜑 → 𝐵 ∈ ℝ )
3 ltadd1d.3 ⊢ ( 𝜑 → 𝐶 ∈ ℝ )
4 ltadd1dd.4 ⊢ ( 𝜑 → 𝐴 < 𝐵 )
5 1 2 3 ltsub2d ⊢ ( 𝜑 → ( 𝐴 < 𝐵 ↔ ( 𝐶 − 𝐵 ) < ( 𝐶 − 𝐴 ) ) )
6 4 5 mpbid ⊢ ( 𝜑 → ( 𝐶 − 𝐵 ) < ( 𝐶 − 𝐴 ) )