Metamath Proof Explorer


Theorem merlem6

Description: Step 12 of Meredith's proof of Lukasiewicz axioms from his sole axiom. (Contributed by NM, 14-Dec-2002) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion merlem6 ( 𝜒 → ( ( ( 𝜓 → 𝜒 ) → 𝜑 ) → ( 𝜃 → 𝜑 ) ) )

Proof

Step Hyp Ref Expression
1 merlem4 ⊢ ( ( 𝜓 → 𝜒 ) → ( ( ( 𝜓 → 𝜒 ) → 𝜑 ) → ( 𝜃 → 𝜑 ) ) )
2 merlem3 ⊢ ( ( ( 𝜓 → 𝜒 ) → ( ( ( 𝜓 → 𝜒 ) → 𝜑 ) → ( 𝜃 → 𝜑 ) ) ) → ( 𝜒 → ( ( ( 𝜓 → 𝜒 ) → 𝜑 ) → ( 𝜃 → 𝜑 ) ) ) )
3 1 2 ax-mp ⊢ ( 𝜒 → ( ( ( 𝜓 → 𝜒 ) → 𝜑 ) → ( 𝜃 → 𝜑 ) ) )