Metamath Proof Explorer


Theorem merlem6

Description: Step 12 of Meredith's proof of Lukasiewicz axioms from his sole axiom. (Contributed by NM, 14-Dec-2002) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion merlem6
|- ( ch -> ( ( ( ps -> ch ) -> ph ) -> ( th -> ph ) ) )

Proof

Step Hyp Ref Expression
1 merlem4
 |-  ( ( ps -> ch ) -> ( ( ( ps -> ch ) -> ph ) -> ( th -> ph ) ) )
2 merlem3
 |-  ( ( ( ps -> ch ) -> ( ( ( ps -> ch ) -> ph ) -> ( th -> ph ) ) ) -> ( ch -> ( ( ( ps -> ch ) -> ph ) -> ( th -> ph ) ) ) )
3 1 2 ax-mp
 |-  ( ch -> ( ( ( ps -> ch ) -> ph ) -> ( th -> ph ) ) )