Metamath Proof Explorer


Theorem modsub12d

Description: Subtraction property of the modulo operation. (Contributed by Mario Carneiro, 9-Sep-2016)

Ref Expression
Hypotheses modadd12d.1 ⊢ ( 𝜑 → 𝐴 ∈ ℝ )
modadd12d.2 ⊢ ( 𝜑 → 𝐵 ∈ ℝ )
modadd12d.3 ⊢ ( 𝜑 → 𝐶 ∈ ℝ )
modadd12d.4 ⊢ ( 𝜑 → 𝐷 ∈ ℝ )
modadd12d.5 ⊢ ( 𝜑 → 𝐸 ∈ ℝ+ )
modadd12d.6 ⊢ ( 𝜑 → ( 𝐴 mod 𝐸 ) = ( 𝐵 mod 𝐸 ) )
modadd12d.7 ⊢ ( 𝜑 → ( 𝐶 mod 𝐸 ) = ( 𝐷 mod 𝐸 ) )
Assertion modsub12d ( 𝜑 → ( ( 𝐴 − 𝐶 ) mod 𝐸 ) = ( ( 𝐵 − 𝐷 ) mod 𝐸 ) )

Proof

Step Hyp Ref Expression
1 modadd12d.1 ⊢ ( 𝜑 → 𝐴 ∈ ℝ )
2 modadd12d.2 ⊢ ( 𝜑 → 𝐵 ∈ ℝ )
3 modadd12d.3 ⊢ ( 𝜑 → 𝐶 ∈ ℝ )
4 modadd12d.4 ⊢ ( 𝜑 → 𝐷 ∈ ℝ )
5 modadd12d.5 ⊢ ( 𝜑 → 𝐸 ∈ ℝ+ )
6 modadd12d.6 ⊢ ( 𝜑 → ( 𝐴 mod 𝐸 ) = ( 𝐵 mod 𝐸 ) )
7 modadd12d.7 ⊢ ( 𝜑 → ( 𝐶 mod 𝐸 ) = ( 𝐷 mod 𝐸 ) )
8 3 renegcld ⊢ ( 𝜑 → - 𝐶 ∈ ℝ )
9 4 renegcld ⊢ ( 𝜑 → - 𝐷 ∈ ℝ )
10 3 4 5 7 modnegd ⊢ ( 𝜑 → ( - 𝐶 mod 𝐸 ) = ( - 𝐷 mod 𝐸 ) )
11 1 2 8 9 5 6 10 modadd12d ⊢ ( 𝜑 → ( ( 𝐴 + - 𝐶 ) mod 𝐸 ) = ( ( 𝐵 + - 𝐷 ) mod 𝐸 ) )
12 1 recnd ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
13 3 recnd ⊢ ( 𝜑 → 𝐶 ∈ ℂ )
14 12 13 negsubd ⊢ ( 𝜑 → ( 𝐴 + - 𝐶 ) = ( 𝐴 − 𝐶 ) )
15 14 oveq1d ⊢ ( 𝜑 → ( ( 𝐴 + - 𝐶 ) mod 𝐸 ) = ( ( 𝐴 − 𝐶 ) mod 𝐸 ) )
16 2 recnd ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
17 4 recnd ⊢ ( 𝜑 → 𝐷 ∈ ℂ )
18 16 17 negsubd ⊢ ( 𝜑 → ( 𝐵 + - 𝐷 ) = ( 𝐵 − 𝐷 ) )
19 18 oveq1d ⊢ ( 𝜑 → ( ( 𝐵 + - 𝐷 ) mod 𝐸 ) = ( ( 𝐵 − 𝐷 ) mod 𝐸 ) )
20 11 15 19 3eqtr3d ⊢ ( 𝜑 → ( ( 𝐴 − 𝐶 ) mod 𝐸 ) = ( ( 𝐵 − 𝐷 ) mod 𝐸 ) )