Metamath Proof Explorer


Theorem moeq

Description: There exists at most one set equal to a given class. (Contributed by NM, 8-Mar-1995) Shorten combined proofs of moeq and eueq . (Proof shortened by BJ, 24-Sep-2022)

Ref Expression
Assertion moeq ∃* 𝑥 𝑥 = 𝐴

Proof

Step Hyp Ref Expression
1 eqtr3 ( ( 𝑥 = 𝐴𝑦 = 𝐴 ) → 𝑥 = 𝑦 )
2 1 gen2 𝑥𝑦 ( ( 𝑥 = 𝐴𝑦 = 𝐴 ) → 𝑥 = 𝑦 )
3 eqeq1 ( 𝑥 = 𝑦 → ( 𝑥 = 𝐴𝑦 = 𝐴 ) )
4 3 mo4 ( ∃* 𝑥 𝑥 = 𝐴 ↔ ∀ 𝑥𝑦 ( ( 𝑥 = 𝐴𝑦 = 𝐴 ) → 𝑥 = 𝑦 ) )
5 2 4 mpbir ∃* 𝑥 𝑥 = 𝐴