Metamath Proof Explorer


Theorem moeq

Description: There exists at most one set equal to a given class. (Contributed by NM, 8-Mar-1995) Shorten combined proofs of moeq and eueq . (Proof shortened by BJ, 24-Sep-2022)

Ref Expression
Assertion moeq ⊢ ∃* x x = A

Proof

Step Hyp Ref Expression
1 eqtr3 ⊢ x = A ∧ y = A → x = y
2 1 gen2 ⊢ ∀ x ∀ y x = A ∧ y = A → x = y
3 eqeq1 ⊢ x = y → x = A ↔ y = A
4 3 mo4 ⊢ ∃* x x = A ↔ ∀ x ∀ y x = A ∧ y = A → x = y
5 2 4 mpbir ⊢ ∃* x x = A