Metamath Proof Explorer


Theorem mulcanad

Description: Cancellation of a nonzero factor on the left in an equation. One-way deduction form of mulcand . (Contributed by David Moews, 28-Feb-2017)

Ref Expression
Hypotheses mulcanad.1 ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
mulcanad.2 ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
mulcanad.3 ⊢ ( 𝜑 → 𝐶 ∈ ℂ )
mulcanad.4 ⊢ ( 𝜑 → 𝐶 ≠ 0 )
mulcanad.5 ⊢ ( 𝜑 → ( 𝐶 · 𝐴 ) = ( 𝐶 · 𝐵 ) )
Assertion mulcanad ( 𝜑 → 𝐴 = 𝐵 )

Proof

Step Hyp Ref Expression
1 mulcanad.1 ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
2 mulcanad.2 ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
3 mulcanad.3 ⊢ ( 𝜑 → 𝐶 ∈ ℂ )
4 mulcanad.4 ⊢ ( 𝜑 → 𝐶 ≠ 0 )
5 mulcanad.5 ⊢ ( 𝜑 → ( 𝐶 · 𝐴 ) = ( 𝐶 · 𝐵 ) )
6 1 2 3 4 mulcand ⊢ ( 𝜑 → ( ( 𝐶 · 𝐴 ) = ( 𝐶 · 𝐵 ) ↔ 𝐴 = 𝐵 ) )
7 5 6 mpbid ⊢ ( 𝜑 → 𝐴 = 𝐵 )