Metamath Proof Explorer


Theorem negcon2i

Description: Negative contraposition law. (Contributed by NM, 25-Aug-1999)

Ref Expression
Hypotheses negidi.1 ⊢ 𝐴 ∈ ℂ
pncan3i.2 ⊢ 𝐵 ∈ ℂ
Assertion negcon2i ( 𝐴 = - 𝐵 ↔ 𝐵 = - 𝐴 )

Proof

Step Hyp Ref Expression
1 negidi.1 ⊢ 𝐴 ∈ ℂ
2 pncan3i.2 ⊢ 𝐵 ∈ ℂ
3 negcon2 ⊢ ( ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ) → ( 𝐴 = - 𝐵 ↔ 𝐵 = - 𝐴 ) )
4 1 2 3 mp2an ⊢ ( 𝐴 = - 𝐵 ↔ 𝐵 = - 𝐴 )