Metamath Proof Explorer


Theorem neldif

Description: Implication of membership in a class difference. (Contributed by NM, 28-Jun-1994)

Ref Expression
Assertion neldif ( ( 𝐴 ∈ 𝐵 ∧ ¬ 𝐴 ∈ ( 𝐵 ∖ 𝐶 ) ) → 𝐴 ∈ 𝐶 )

Proof

Step Hyp Ref Expression
1 eldif ⊢ ( 𝐴 ∈ ( 𝐵 ∖ 𝐶 ) ↔ ( 𝐴 ∈ 𝐵 ∧ ¬ 𝐴 ∈ 𝐶 ) )
2 1 simplbi2 ⊢ ( 𝐴 ∈ 𝐵 → ( ¬ 𝐴 ∈ 𝐶 → 𝐴 ∈ ( 𝐵 ∖ 𝐶 ) ) )
3 2 con1d ⊢ ( 𝐴 ∈ 𝐵 → ( ¬ 𝐴 ∈ ( 𝐵 ∖ 𝐶 ) → 𝐴 ∈ 𝐶 ) )
4 3 imp ⊢ ( ( 𝐴 ∈ 𝐵 ∧ ¬ 𝐴 ∈ ( 𝐵 ∖ 𝐶 ) ) → 𝐴 ∈ 𝐶 )