Metamath Proof Explorer


Theorem nf5i

Description: Deduce that x is not free in ph from the definition. (Contributed by Mario Carneiro, 11-Aug-2016)

Ref Expression
Hypothesis nf5i.1 ( 𝜑 → ∀ 𝑥 𝜑 )
Assertion nf5i 𝑥 𝜑

Proof

Step Hyp Ref Expression
1 nf5i.1 ( 𝜑 → ∀ 𝑥 𝜑 )
2 nf5-1 ( ∀ 𝑥 ( 𝜑 → ∀ 𝑥 𝜑 ) → Ⅎ 𝑥 𝜑 )
3 2 1 mpg 𝑥 𝜑