Metamath Proof Explorer


Theorem nfbii

Description: Equality theorem for the non-freeness predicate. (Contributed by Mario Carneiro, 11-Aug-2016) df-nf changed. (Revised by Wolf Lammen, 12-Sep-2021)

Ref Expression
Hypothesis nfbii.1 ( 𝜑𝜓 )
Assertion nfbii ( Ⅎ 𝑥 𝜑 ↔ Ⅎ 𝑥 𝜓 )

Proof

Step Hyp Ref Expression
1 nfbii.1 ( 𝜑𝜓 )
2 nfbiit ( ∀ 𝑥 ( 𝜑𝜓 ) → ( Ⅎ 𝑥 𝜑 ↔ Ⅎ 𝑥 𝜓 ) )
3 2 1 mpg ( Ⅎ 𝑥 𝜑 ↔ Ⅎ 𝑥 𝜓 )