Metamath Proof Explorer


Theorem nfcd

Description: Deduce that a class A does not have x free in it. (Contributed by Mario Carneiro, 11-Aug-2016)

Ref Expression
Hypotheses nfcd.1 𝑦 𝜑
nfcd.2 ( 𝜑 → Ⅎ 𝑥 𝑦𝐴 )
Assertion nfcd ( 𝜑 𝑥 𝐴 )

Proof

Step Hyp Ref Expression
1 nfcd.1 𝑦 𝜑
2 nfcd.2 ( 𝜑 → Ⅎ 𝑥 𝑦𝐴 )
3 1 2 alrimi ( 𝜑 → ∀ 𝑦𝑥 𝑦𝐴 )
4 df-nfc ( 𝑥 𝐴 ↔ ∀ 𝑦𝑥 𝑦𝐴 )
5 3 4 sylibr ( 𝜑 𝑥 𝐴 )