Metamath Proof Explorer


Theorem nfcii

Description: Deduce that a class A does not have x free in it. (Contributed by Mario Carneiro, 11-Aug-2016)

Ref Expression
Hypothesis nfcii.1 ⊢ ( 𝑦 ∈ 𝐴 → ∀ 𝑥 𝑦 ∈ 𝐴 )
Assertion nfcii Ⅎ 𝑥 𝐴

Proof

Step Hyp Ref Expression
1 nfcii.1 ⊢ ( 𝑦 ∈ 𝐴 → ∀ 𝑥 𝑦 ∈ 𝐴 )
2 1 nf5i ⊢ Ⅎ 𝑥 𝑦 ∈ 𝐴
3 2 nfci ⊢ Ⅎ 𝑥 𝐴