Metamath Proof Explorer


Theorem nfs1

Description: If y is not free in ph , x is not free in [ y / x ] ph . Usage of this theorem is discouraged because it depends on ax-13 . Check out nfs1v for a version requiring less axioms. (Contributed by Mario Carneiro, 11-Aug-2016) (New usage is discouraged.)

Ref Expression
Hypothesis nfs1.1 𝑦 𝜑
Assertion nfs1 𝑥 [ 𝑦 / 𝑥 ] 𝜑

Proof

Step Hyp Ref Expression
1 nfs1.1 𝑦 𝜑
2 1 nf5ri ( 𝜑 → ∀ 𝑦 𝜑 )
3 2 hbsb3 ( [ 𝑦 / 𝑥 ] 𝜑 → ∀ 𝑥 [ 𝑦 / 𝑥 ] 𝜑 )
4 3 nf5i 𝑥 [ 𝑦 / 𝑥 ] 𝜑