Metamath Proof Explorer


Theorem nmmul

Description: The norm of a product in a normed ring. (Contributed by Mario Carneiro, 5-Oct-2015)

Ref Expression
Hypotheses nmmul.x ⊢ 𝑋 = ( Base ‘ 𝑅 )
nmmul.n ⊢ 𝑁 = ( norm ‘ 𝑅 )
nmmul.t ⊢ · = ( .r ‘ 𝑅 )
Assertion nmmul ( ( 𝑅 ∈ NrmRing ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ( 𝑁 ‘ ( 𝐴 · 𝐵 ) ) = ( ( 𝑁 ‘ 𝐴 ) · ( 𝑁 ‘ 𝐵 ) ) )

Proof

Step Hyp Ref Expression
1 nmmul.x ⊢ 𝑋 = ( Base ‘ 𝑅 )
2 nmmul.n ⊢ 𝑁 = ( norm ‘ 𝑅 )
3 nmmul.t ⊢ · = ( .r ‘ 𝑅 )
4 eqid ⊢ ( AbsVal ‘ 𝑅 ) = ( AbsVal ‘ 𝑅 )
5 2 4 nrgabv ⊢ ( 𝑅 ∈ NrmRing → 𝑁 ∈ ( AbsVal ‘ 𝑅 ) )
6 4 1 3 abvmul ⊢ ( ( 𝑁 ∈ ( AbsVal ‘ 𝑅 ) ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ( 𝑁 ‘ ( 𝐴 · 𝐵 ) ) = ( ( 𝑁 ‘ 𝐴 ) · ( 𝑁 ‘ 𝐵 ) ) )
7 5 6 syl3an1 ⊢ ( ( 𝑅 ∈ NrmRing ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ( 𝑁 ‘ ( 𝐴 · 𝐵 ) ) = ( ( 𝑁 ‘ 𝐴 ) · ( 𝑁 ‘ 𝐵 ) ) )