Metamath Proof Explorer


Theorem nnexpcl

Description: Closure of exponentiation of nonnegative integers. (Contributed by NM, 16-Dec-2005)

Ref Expression
Assertion nnexpcl ( ( 𝐴 ∈ ℕ ∧ 𝑁 ∈ ℕ0 ) → ( 𝐴𝑁 ) ∈ ℕ )

Proof

Step Hyp Ref Expression
1 nnsscn ℕ ⊆ ℂ
2 nnmulcl ( ( 𝑥 ∈ ℕ ∧ 𝑦 ∈ ℕ ) → ( 𝑥 · 𝑦 ) ∈ ℕ )
3 1nn 1 ∈ ℕ
4 1 2 3 expcllem ( ( 𝐴 ∈ ℕ ∧ 𝑁 ∈ ℕ0 ) → ( 𝐴𝑁 ) ∈ ℕ )